Menu Nitto ATP Finals The O2, London | 15-22 NOV.

Format

Format

The Nitto ATP Finals has a round-robin format, with eight players/teams divided into two groups of four. The eight seeds are determined by the ATP Rankings and ATP Doubles Team Rankings on the Monday after the last ATP World Tour tournament of the calendar year. All singles matches are the best of three tie-break sets, including the final. All doubles matches are two sets (no ad) and a Match Tie-break.

Draw

The top seeded players/team is placed in Group A and the second seeded player/team is placed in Group B. Players/teams seeded 3 and 4, 5 and 6, 7 and 8, are then drawn in pairs with the first drawn placed in Group A. Each player/team plays the three other players/teams in his group. The winner of each group (best overall record) is placed in separate semi-final brackets, with the top player/team in Group A playing the runner-up in Group B, and vice versa. If two or more players/teams are tied after the round robin matches, the ties are broken by the Tie-Break Procedure.

The Finals Club, an initiative launched by the ATP in 2015 as a way of celebrating the past champions and heritage of the season-ending tournament since its inception in 1970, has honoured former champions through the naming of groups over the past four years. This year’s groups will be named as follows:

In singles:
- Group A was named in honour of Andre Agassi, the 1990 winner and 14-time qualifier.
- Group B was named in honour of Bjorn Borg, the 1979 and 1980 winner.

In doubles:
- Group A was named in honour of Max Mirnyi, the 2006 and 2011 winner.
- Group B was named in honour of Jonas Bjorkman, the 1994 and 2006 winner.

Semi-final Qualifying Procedure

The final standings of each group is determined by the first of the following methods that apply:
a) Greatest number of wins;
b) Greatest number of matches played;
    Comment: 2-1 won-loss record beats a 2-0 won-loss record; a 1-2 record beats a 1-0 record.
c) Head-to-head results if only two (2) players are tied,
d) If three (3) players are tied, then...
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